tentukan ph larutan apabila 400 ml larutan NH4OH 0.5M dicampur dengan 100 ml larutan Nh4Cl 0.5 m (kb NH40H = 1,8×10^-5)

[tex] {oh }^{ - } = kb \times \frac{n \: asam}{n \: garam} \\ {oh}^{ - } = 1.8 \times {10}^{ - 5} \times \frac{400 \times 0.5}{100 \times 0.5} \\ {oh}^{ - } = 1.8 \times {10}^{ - 5} \times 4 \\ {oh}^{ - } = 7.2 \times {10}^{ - 5 } [/tex]
POH =5-log7,2
ph = 14-(5-log7.2)
ph = 9 + log7.2