Diketahui f(x)=x+6 dan (gof) (x) =x²+10x+27. Rumus fungsi g(x+1) ....a. x²-2b. x²+2c. x²+2x+3d. x²+10x+27e. x²+10x+30tolong dijawab ya

F'(x) = x-6

(Gof) (x) = g (f(x))

G(x) = g (f' (x))
G(x) = (x-6)^2 + 10 (x-6) + 27
G(x) = x^2 - 2x +3

G(x+1) = (x+1)^2 - 2(x+1) + 3
G(x+1) = x^2 + 2
Jadi jawabanya B ya gan
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