Tentukan persamaan garis singgung y=√x dititik (4,2)

y=√x dititik (4,2)

y' = m = fungsi turunan =
[tex] \frac{1}{2 \sqrt{x} } = \frac{1}{2 \times ( {x}^{ \frac{1}{2} } ) } =\frac{1}{2 \times ( {4}^{ \frac{1}{2} } ) } = \frac{1}{4} [/tex]
pgs =
y - b = m(x-a)
y - 2 = ¼(x-4)
4y = x + 4
y = ¼x + 1

m = y'
    = 1/2 x⁻¹/²
    = 1/ 2√x
    = 1/ 2√4
    = 1/4

y - b = m (x-a)
y - 2 = 1/4 (x-4)
4y - 8 = x-4
x-4y+4 = 0