tolong jawab buat besok.....

GSPL^2 = d^2 - (R-r)^2
AB^2 = CD^2 - (AC-BD)^2
AB^2 = 9^2 - (4-3)^2
AB^2 = 81 - 1
AB^2 = 80
AB = akar 80
[tex]ab \: = 4 \sqrt{5} \: cm[/tex]
B

Mapel : Matematika

Kelas : 8

Bab : Garis Singgung Lingkaran
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AC = 4 cm
CD = 9 cm
BD = 3 cm


Ditanya :
→ AB ( gspl)


AB = √[(CD² - (AC - BD) ²]

AB = √[(9² - (4 - 3)]

AB = √81 - 1

AB = √80

AB = √(16x5

AB =√16 x √5

AB = 4√5