luas permukaan bangun tersebut adalah??

s^2 = t^2 + r^2
s^2 = (34 - (1/2 × 20))^2 + (1/2 × 20)^2
s^2 = (34 - 10)^2 + 10^2
s^2 = 24^2 + 10^2
s^2 = 576 + 100
s^2 = 676
s = 26 cm

r = 1/2 × d
r = 1/2 × 20
r = 10 cm

L permukaan bangun
= L 1/2 bola + L selimut kerucut
= (1/2 × 4 × phi × r^2) + (phi × r × s)
= (2 × 3,14 × 10 × 10) + (3,14 × 10 × 26)
= 628 + 816,4
= 1444,4 cm^2 (C)

satuan pilihan salah tdk ada kuadrat