Sebanyak 1,48 gram ca(oh)2 dilarutkan dalam air hingga 200 ml. Hitunglah ph larutan tersebut

[tex]m = \frac{gr}{mr} \times \frac{1000}{v} \\ m = \frac{1.48}{74} \times \frac{1000}{200} \\ m = 0.02 \times 5 \\ m = 0.1[/tex]
[OH-] = M × valensi basa
[OH-] = 0.1 × 2
[OH-] = 2×10^-1

pOH = 1-log2
pH = 14-(1-log2)
pH = 13+log2