ini bagaimana ya? tolong caranya

[tex] = 2 \sqrt{8} - 4 \sqrt{18} + \sqrt{32} \\ = 2 \sqrt{4 \times 2} - 4 \sqrt{9 \times 2} + \sqrt{16 \times 2} \\ = 2 \times 2 \sqrt{2} - 4 \times 3 \sqrt{2} + 4 \sqrt{2} \\ = 4 \sqrt{2} - 12 \sqrt{2} + 4 \sqrt{2} \\ = - 4 \sqrt{2} [/tex]

2√8 = 2x2 √2
       = 4√2

4√18 = 4 x 3 √2 
         = 12√2

√32 = 4√2

Jadi , 2√8 - 4√18 + √32
= 4√2 - 12√2 + 4√2 
= -4 √2  (A)