Kuat arus yang mengalir pada kumpran primer adalah

Diket :
Np = 220 v
Ns = 640
Vp = 220 v
R s = 8 ohm

Dit : Arus Primer......?

Jwb :

# Tegangan sekunder

Vs = ( Ns . Vp ) / Np
Vs = ( 640 . 220 ) / 220
Vs =140.800 / 220
Vs = 640 volt

# Arud sekunder

Is = Vs / R s
Is = 640 / 8
Is = 80 A

# Arus primer

Ip = ( Vs . Is ) / Vp
Ip = ( 640 . 80 ) /220
Ip = 51200 /220
Ip = 234,7

Jadi Arus ptimernya 234,7 A

Diket :
Np = 220 lilitan
Ns = 640 lilitan
Vp = 220 Volt
Rs = 8 Ω

Dit :
Ip?

Jawab :

Tegangan Sekunder :
Vp / Vs = Np / Ns
220 / Vs = 640 / 220
Vs = 32 / 11 × 220
Vs = 640 Volt

Kuat Arus Sekunder :
Vs = Is × Rs
640 = Is × 8
Is = 80 Ampere

Kuat Arus Primer :
Vp / Vs = Is / Ip
220 / 640 = 80 / Ip
Ip = 51200 / 220
Ip = 234, 7 Ampere

#semogamembantu

JADIKAN JAWABAN TERBAIK