Matematika

Pertanyaan

bentuk sederhana dari
bentuk sederhana dari

1 Jawaban


  • [tex]1. \\ ( \sqrt{12} + \sqrt{32})( \sqrt{8} - \sqrt{27} ) \\ = \sqrt{12.8} - \sqrt{12.27} + \sqrt{32.8} - \sqrt{32.27} \\ = \sqrt{96} - \sqrt{324} + \sqrt{256} - \sqrt{864} \\ = 4 \sqrt{6} - 18 + 16 - 12 \sqrt{6} \\ = - 8 \sqrt{6} - 2[/tex]

    [tex]2. \\ \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{32} + 2 \sqrt{3} } \\ = \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{32} + 2 \sqrt{3} } \times \frac{ \sqrt{32} - 2 \sqrt{3} }{ \sqrt{32} - 2 \sqrt{3} } \\ = \frac{ \sqrt{32.3} - 2.3 + \sqrt{32.2} - 2 \sqrt{2.3} }{32 - 4.3} \\ = \frac{ \sqrt{96} - 6 + \sqrt{ 64} - 2 \sqrt{6} }{20} \\ = \frac{4 \sqrt{6} - 2 \sqrt{6} - 6 + 8}{20} \\ = \frac{2 \sqrt{6 } + 2 }{20} \\ = \frac{2( \sqrt{6} + 1)}{20} \\ = \frac{ \sqrt{6} + 1 }{10} [/tex]