tentukan pusat dan jari jari lingkaran x²+y²+14xt10y+42=0

a=14 b=10 c=42
P(a,b)
a=14/-2 =-7
b=10/-2=-5
P(-7;-5)

[tex]r =\sqrt{ {a}^{2} + {b}^{2} - c} \\ = \sqrt{49 +25 - 42 } \\ = \sqrt{32} = 4 \sqrt{2} [/tex]