jawablah pernyataan tersebut no.37?...

51,54,57.....249

[tex]un = a + (n - 1)b \\ 249 = 51 + (n - 1)3 \\ 198 = 3n - 3 \\ 201 = 3n \\ 67 = n[/tex]

[tex]s67 = \frac{n}{2} (2a + (n - 1)b) \\ s67 = \frac{67}{2} (102 + (66 \times 3) \\ s67 = \frac{67}{2} (300) \\ s67 = 10.050[/tex]

a=51
b=3
un=249

un=a+(n-1)b
249=51+(n-1)3
249=51+3n-3
249=48+3n
248-48=3n
201=3n
201/3=n
67=n

sn=n/2(2a+(n-1)b)
567=67/2(2.51+(67-1)3)
=67/2(102+66.3)
=67(102+198)
=67/2(coret duanya) (300) (coret tiga ratus nya dan diatas coret itu 150)
=10.050 B