Tentukan luas segitiga PQR, PR = 15 cm, QR = 12 cm, dan∠R = 120°
Matematika
zulvan13
Pertanyaan
Tentukan luas segitiga PQR, PR = 15 cm, QR = 12 cm, dan∠R = 120°
1 Jawaban
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1. Jawaban EllentheodoraF
PR^2 = QR^2 + PQ^2
15^2 = 12^2 + PQ^2
225 = 144 + PQ^2
225-144 = PQ^2
81 = PQ^2
[tex] \sqrt{81} [/tex]
= 9
luas segitiga = 1/2 x a x t
= 1/2 x 12 x 9
= 6 x 9
= 54