Disuatu desa terdapat 9% orang albino. Tentukan persentase orang normal homozigot

Hardy Weinberg
p^2 + 2pq + q^2

Albino = q^2 = 9% = 0.09
q = akar 0.09 = 0.3

p = 1 - 0.3 = 0.7

normal homozigot = p^2 = 0.7^2 = 0.49 atau 49%
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I hope this is true for you, have a nice day !
Brainly is the Best !