Matematika

Pertanyaan

Jika a log 81 - 2 a log 27 + a log 243 = 6

1 Jawaban

  • alog81 - 2alog27 + alog243 = aloga^6
    alog3⁴ - alog3^6 + alog3^5 = aloga^6
    3⁴/3^6 x 3^5 = a^6
    3^(4-6+5) = a^6
    3³ = a^6
    a = √3

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