Matematika

Pertanyaan

nilai simpangan baku dari data 6,6,6,7,7,8,8,8 adalah

1 Jawaban

  • [tex]x= \frac{6+6+6+7+7+8+8+8}{8}=7 [/tex]

    [tex]S= \sqrt{ \frac{(6-7)^2+(6-7)^2+(6-7)^2+(7-7)^2+(7-7)^2+(8-7)^2+(8-7)^2+(8-7)^2}{8} } [/tex]
    [tex]S= \sqrt{ \frac{(-1)^2+(-1)^2+(-1)^2+(0)^2+(0)^2+(1)^2+(1)^2+(1)^2}{8} } [/tex]
    [tex]S= \sqrt{ \frac{1+1+1+0+0+1+1+1}{8} }= \sqrt{\frac{6}{8} } = \frac{1}{2} \sqrt \frac{6}{2} = \frac{1}{2} \sqrt{3} [/tex]

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