Tentukan kordinat kutub dari(men2 akar 3 men2

[tex] - 2 \sqrt{3} \: \: dan \: \: - 2[/tex]
cari nilai r
[tex]r = \sqrt{ {( - 2 \sqrt{3} )}^{2} + {( - 2}^{2} ) } \\ = \sqrt{12 + 4} \\ = \sqrt{16} \\ = 4[/tex]
cari alfa
[tex]tan \: \: a = \frac{ - 2}{ - 2 \sqrt{3} } \\ tan \: \: a = \frac{1}{ \sqrt{3} } \\ tan \: \: a = \frac{1}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } \\ tan \: \: a = \frac{1}{3} \sqrt{3} [/tex]
berada di kuadran III maka
[tex]180 + 30 = 210[/tex]