Hitunglah pH dari larutan H3PO4 0,02M?

Mapel; Kimia
Kelas: XI
Materi: Asam Basa

Jawab
H3PO4
[H+] = x.n
[H+] = 2×0.02
[H+] 0.04
[H+] = 4×10-²

pH=> -log[H+]
pH=> -log 4×10-²
pH= 4-log 2
pH => 4-0.3
pH=> 3,7