jika diketahui f(x)=2-x, g(x)=x²+1, dan h(x)=3x, maka nilai dari (hogof) (3)=

g(x)=(2-x)^2+1 = (2-x)(2-x)+1 = x^2-4x+5
h(x)= 3 (x^2-4x+5) = 3x^2-12x+15
h(3) = 3(3)^2-12(3)+15(3) = 36

(hogof)= 3(x2+1)
= 3xkuadrat + 1
=3(2-x)kuadrat + 1
=3(4-4x+x) + 1
=12-12x+x+ 1
=13-12(3) + (3)
=13-36+3
=-20