Nilai dari [tex] \sqrt{72} +3 \sqrt{32} - 2 \sqrt{50} [/tex] adalah.... A. 10 [tex] \sqrt{72} [/tex] B.8 [tex] \sqrt{2} [/tex] C.6 [tex] \sqrt{ \sqrt{2} } [/

√72 + 3√32 -2√50
= √36×2 + 3√16×2 - 2√25×2
= 6√2 + 3.4√2 - 2.5√2
= 6√2 + 12√2 - 10√2
= 8√2

Jawabannya B

[tex] \sqrt{72} + 3 \sqrt{32} - 2 \sqrt{50} \\ = \sqrt{36.2} + 3 \sqrt{16.2} - 2 \sqrt{25.2} \\ = 6 \sqrt{2} + 3.4 \sqrt{2} - 2.5 \sqrt{2} \\ = 6 \sqrt{2} + 12 \sqrt{2} - 10 \sqrt{2} \\ = 8 \sqrt{2} [/tex]
jawabannya B