bantu dong ya pliss,pake cara f(x)=(x²+3)pangkat 4

[tex]anggap \: f(x) = y \\ f(x) = ( {x}^{2} + 3) {}^{4} \\ y = ( {x}^{2} + 3) {}^{4} \\ y = {x}^{8} + {3}^{4} \\ y = {x}^{8} +81 \\ {x}^{8} + 81 = y \\ {x}^{8} = y - 81 \\ x = \sqrt[8]{y - 81} \\ f {}^{ - 1} (x) = \sqrt[8]{y - 81} \\ {f}^{ - 1} (x) = \sqrt[8]{x - 81} [/tex]
Semoga bermanfaat.....
-Prisco