Tolong jawab beserta caranya

8) 3√2 x √75 : √54
3√2 x 5√3 : 3√6
15√6 : 3√6 = 5 (C)

9) 6√8 - 4√32 + √128
6x2√2 - 4x4√2 + 8√2
12√2 -16√2 + 8√2 = 4√2 (B)

10) 2√18 +√32 - 4√8
2.3√2 + 4√2 - 4x2√2
6√2 +4√2 - 8√2 =2√2 (B)

11) 5√20 + √80 - 2√45
5x2√5 + 4√5 - 2x3√5
10√5 + 4√5 - 6√5 = 8√5 (C)

12) 4√18 : 3√12
4x3√2 : 3x2√3
12√2 : 6√3 = 2√6/3 (D)

13) 2√12 x √18
2x2√3 x 3√2
4√3 x 3√2 = 12√6 (C)

Semoga bermanfaat ^_^

indikator 2
8)
[tex]3 \sqrt{2} \times 5 \sqrt{3} \div 3 \sqrt{6} = \\ 15 \sqrt{6} \div 3 \sqrt{6} = \\ (c) \: 5[/tex]
9)
[tex]12 \sqrt{2} - 16 \sqrt{2} + 8 \sqrt{2} = \\ (b) \: 4 \sqrt{2} [/tex]
10)
[tex]6 \sqrt{2} + 4 \sqrt{2} - 8 \sqrt{2} = \\ (b) \: 2 \sqrt{2} [/tex]
11)
[tex]10 \sqrt{5} + 4 \sqrt{5} - 6 \sqrt{5} = \\ (c) \: 8 \sqrt{5} [/tex]
12)
[tex]12 \sqrt{2} \div 6 \sqrt{3} = \\ (b) \: 2 \sqrt{6} [/tex]
13)
[tex]4 \sqrt{3} \times 3 \sqrt{2} = \\ (c) \: 12 \sqrt{6} [/tex]
smoga membantu ^_^
omong2, soalnya kok sama dengan saya ya?