Diketahui deret bilangan 2+6+18+54+.. Tentukan s10 Tolong bantu pakai jalan yaa kak,bg

[tex]s10 = \frac{a( {r}^{n} - 1) }{r - 1} \\ s10 = \frac{2( {3}^{10 } - 1)}{3 - 1} \\ s10 = \frac{2(59.049 - 1)}{2} \\ s10 = 59.049 - 1 \\ s10 = 59.048[/tex]