persamaan garis lurus melalui titik K (4,-3) dan sejajar garis 2x - 5y - 10 = 0 adalah

-5y = -2x + 10
y = 2/5x - 2
gradien = 2/5
klo garis sejajar gradiennya sama

y-y1 = m(x-x1)
y-(-3) = 2/5(x-4)
y + 3= 2/5x - 8/5
y = 2/5x -8/5 - 15/5
y = 2/5x - 23/5
5y = 2x - 23

-5y = -2x + 10
y = 2/5x - 2
gradien = 2/5

y-y1 = m(x-x1)
y-(-3) = 2/5(x-4)
y + 3= 2/5x - 8/5
y = 2/5x -8/5 - 15/5
y = 2/5x - 23/5
5y = 2x - 23
Maaf klo salah