Hitunglah pH larutan NH3 0,04m, jika Kb NH : 10 pangkat -6

[OH^(-)] = akar( kb×Mb)
= akar (10^-6 × 0.04)
= akar (4 × 10^-8)
= 2 × 10^-4
POH = -log 2 × 10^-4
= 4 - log 2
= 4 - 0.301
= 3, 699
PH = 14- 3,699
=10, 301
smoga bermanfaat