3ײ+4×+1=0 tentukan akar akar persamaan kuadrat tersebut

3x^2 + 4x + 1 = 0
pq = ac = 3 × 1 = 3
p + q = b = 4
p = 3
q = 1

3x^2 + 3x + x + 1 = 0
3x(x + 1) + 1(x + 1) = 0
(3x + 1) (x + 1) = 0
3x + 1 = 0
3x = -1
x1 = -1/3
atau
(x + 1) = 0
x2 = -1

x1,x2 = -1/3,-1

Semoga membantu ^^