50 ml larutan hcl 0,01 m direaksikan dengan 50 ml larutan naoh 0,01 m. tentukanlah ph awal kedua larutan dan ph hasil reaksinya

diketahui
50 ml HCl 0.01 M
50 ml NaOH 0.01 M

ditanya : ph awal dan ph akhir?

jawab:
HCl
[H+] = M × valensi asam
[H+] = 0.01 × 1
[H+] = 10^-2
ph = 2

NaOH
[OH-] = M × valensi basa
[OH-] = 0.01 × 1
[OH-] = 10^-2
poh = 2
ph = 14-2 = 12

ph campuran
NaOH + HCl --> NaCl
=basa kuat + asan kuat
=netral
ph = 7