koordinat titik balik fungsi kuadrat f(x)=2x2-4x-6 adalah

[tex]f(x) = {2x}^{2} - 4x - 6[/tex]
a = 2,, b = -4,, c = -6

nilai x puncak

[tex]x = \frac{ - b}{2a} = \frac{ - ( - 4)}{2.2} = \frac{4}{4} = 1[/tex]

cari D dulu
[tex]d = {b}^{2} - 4ac \\ = {( - 4)}^{2} - 4.2.( - 6) \\ = 16 + 48 \\ = 64 [/tex]
maka nilai y puncak
[tex]y = \frac{ - d}{4a} = \frac{ - 64}{4.2} = \frac{ - 64}{8} = - 8[/tex]

maka titik baliknya ( 1, - 8 )