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[tex] \sqrt[3]{1000 } = 10[/tex]
10 = panjang kubus
[tex]panjang \: balok \: = 2 \times 10 = 20 \: cm[/tex]
[tex]tinggi \: balok \: = \frac{1}{2} \times 10 = 5cm[/tex]
[tex]lebar \: balok \: = 20 \div 2 = 10cm[/tex]
jadi,luas seluruh permukaan balok adalah
[tex]a.2 \times p \times t \\ \: 2 \times 20 \times 5 = 200 {cm}^{3} [/tex]
[tex]b.2 \times t \times l \\ \: \: 2 \times 5 \times 10 = 100 {cm}^{3} [/tex]
[tex]c.2 \times p \times l \\ \: \: 2 \times 20 \times 10 = 400 {cm}^{3} [/tex]

=200+100+400
[tex] = 700 {cm}^{3} [/tex]

2.a.ukuran akuarium
p=30cm
l = 15 cm
t = 20 cm

v = p \times l \times t
v = 30 \times 15 \times 20 9.000 {cm}^{3} [/tex]

b.luas permukaan
= 2 \times (pl + pt + lt)
= 2 \times (30 \times 45 + 30 \times 20 + 15 \times 20)
= 2 \times (450 + 600 + 300)
=2 \times (1350)
= 2.700 {cm}^{2} [/tex]

3.a.v=1331 {cm}^{3} [/tex]
1331 = s {cm}^{3} [/tex]
s = 3√1331
s = 11 rusuknya 11 cm
b.v=10 \times 1331 =13310 {cm}^{3} [/tex]

4.rusuk kubus semula = 3√343 = 7 cm
rusuk kubus baru = 4 di kali 7 cm = 28 cm
rusuk kubus baru = s di kali s di kali s = 28 di kali 28 di kali 28 = 21952 cm pangkat 3

semoga bermanfaat