persamaan garis yang melalui titik(0,1)dan(1,6),adalah?

Kelas 8 Matematika
Bab Persamaan Garis

(y - y1)/(y2 - y1) = (x - x1)/(x2 - x1)
(y - 1)/(6 - 1) = (x - 0)/(1 - 0)
(y - 1)/5 = x/1
y - 1 = 5x
y = 5x + 1

(0,1) --> (x1, y1)
(1,6)--> (x2, y2)

Persamaannya:
y-y1/y2-y1 = x-x1/x2-x1
y-1/6-1 = x-0/1-0
y-1/5 = x/1
1(y-1) =5x
y-1 = 5x
y=5x+1
Atau
y-5x-1 = 0
Atau - 5x+y-1=0